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112=(3^2x/3^5x)
We move all terms to the left:
112-((3^2x/3^5x))=0
Domain of the equation: 3^5x))!=0We multiply all the terms by the denominator
x!=0/1
x!=0
x∈R
-((3^2x+112*3^5x))=0
We calculate terms in parentheses: -((3^2x+112*3^5x)), so:
(3^2x+112*3^5x)
We get rid of parentheses
3^2x+112*3^5x
Wy multiply elements
336x^5+3^2x
We do not support expression: x^5
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